What are the odds of getting 3x the same champs?

Trying to get Fury. Opened 3 skill/mutant crystals, and got 3x Electra.
Come on Kabam!!!! Merry Christmas s*cker.

Comments

man i wish that happened to me with aegon. There are 65 mutant/skills available as 5* but some aren't in the pool, but I'm not gonna bother counting. it'd just be 1/65 * 1/65 to get 3 of the same people

KattohS

Trying to get Fury. Opened 3 skill/mutant crystals, and got 3x Electra.
Come on Kabam!!!! Merry Christmas s*cker.

These crystals are BS.

Only good for duping and getting champs for arena.

KevanproG

I pulled so many bad champs in the duel crystal but in normal crystal I pull S+ Champs lol

Pintzz

I pulled dd classic 3 times in a row as a 6 star last year when it was much harder getting stars. Was a low time in mcoc life hahaha

unknown

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SaltE_Wenis69

I dunno.. you tell me

#NeverForget

And while i didnt screenshot it. Around 3-4 months after this happend i swear to god i pulled 3 6* gamoras in a row

ooof i am very sorry for your loss

DNA3000

Three identical pulls from the dual class crystals happens about once in 3600 openings, more or less, depending on the crystal type. Three out of five being identical, as above, is much easier: it happens about once every 360 openings or so.

MarshMarlo

Hey guys. He's asking for the odds.

Someone care to do the math and show it. Im bored today.

SpideyFunko

Hey guys. He's asking for the odds.

Someone care to do the math and show it. Im bored today.

Three identical pulls from the dual class crystals happens about once in 3600 openings, more or less, depending on the crystal type. Three out of five being identical, as above, is much easier: it happens about once every 360 openings or so.

DNA3000

Hey guys. He's asking for the odds.

Someone care to do the math and show it. Im bored today.

If the number of champions in the crystal is N, the odds of pulling three identical champs is one in N^2. So ballparking the number as about 60, the odds are about one in 3600. This is because the first champ can be anything (so the odds of doing that are 100%) but the next two must match it, each time the odds against that are one in N. So it is 1 x 1/N x 1/N = 1/N^2, or one in N^2.

Some people think the odds are one in N^3, or in this case about one in 216,000. That's wrong, because those are the odds of pulling a specific champ three times in a row. If the odds of pulling, say Elektra three times in a row is one in 216,000, the odds of pulling *any* champ three times in a row can't also be that. The odds of pulling any champ three times in a row would be the odds of pulling Elektra three times in a row, plus the odds of pulling Falcon three times in a row, plus etc etc etc. If there are N different champs in the crystal, the odds of pulling any one specific champ three times in a row would be one in N^3, but then there are N ways to do that (one for each champ), which means the odds of doing it for any champ would be N x (1/N^3) which is 1/N^2, the number given above. Two different lines of thought which reach the same correct answer.

Gardener

I dunno.. you tell me

#NeverForget

And while i didnt screenshot it. Around 3-4 months after this happend i swear to god i pulled 3 6* gamoras in a row

and those were from Basics not dual class so this is rarer

Thicco_Mode

Hey guys. He's asking for the odds.

Someone care to do the math and show it. Im bored today.
If the number of champions in the crystal is N, the odds of pulling three identical champs is one in N^2. So ballparking the number as about 60, the odds are about one in 3600. This is because the first champ can be anything (so the odds of doing that are 100%) but the next two must match it, each time the odds against that are one in N. So it is 1 x 1/N x 1/N = 1/N^2, or one in N^2.

Some people think the odds are one in N^3, or in this case about one in 216,000. That's wrong, because those are the odds of pulling a specific champ three times in a row. If the odds of pulling, say Elektra three times in a row is one in 216,000, the odds of pulling *any* champ three times in a row can't also be that. The odds of pulling any champ three times in a row would be the odds of pulling Elektra three times in a row, plus the odds of pulling Falcon three times in a row, plus etc etc etc. If there are N different champs in the crystal, the odds of pulling any one specific champ three times in a row would be one in N^3, but then there are N ways to do that (one for each champ), which means the odds of doing it for any champ would be N x (1/N^3) which is 1/N^2, the number given above. Two different lines of thought which reach the same correct answer.

yeah i usually use the second method to explain because I feel like it makes more intuitive sense

Will3808

Oh wow. That’s crazy

Will3808

I’ve seen a few openings like this with good people. There was a picture of someone pulling 2 of 6* CGR out of 3 featured crystals.

Deacon

i've had that happen more than i care to share smh