Guys/gals - help me with Cosmic awakening decision please...

Results of poll will determine who it is, cuz I just can't decide. Obvi the first 2 options are CG and CGR - but I've heard good things about Angela...so I turn to the community at large...

Comments

Pikolu

Corvus is nice with dupe, but it isn't required, whereas Angela needs dupe to be good

JohnLocke117

Angela's sig ability will help you the most compared to the others. CGR doesn't really need the dupe, Corvus gets cheat death but it is niche and usable in few places only aside from special quests once in a while. I would recommend angela.

Malreck04

Corvus' sig is one of the best in game, but only give it to him if you plan to use him often. Otherwise Angela, she becomes debuff immune essentially with a couple of buffs.

Xva23

Corvus gets most use at sig 1. If you have a lot of sig stones, Angela might be better

Real_Madrid_76_2

Shang Chi challenge cheese 🍕. Oh wait where am I, multiverse? I entered another timeline where I only see cataclysm type thingies

Yodabolt21

Unless you get Angela to high sig right away.

Rasilover

Corvus’ sig ability is legit ridiculously strong

Kerneas

I feel like Angela has more uses with her sig vs without it than CG does

Tainto

I feel like Angela has more uses with her sig vs without it than CG does

Yeah that’s what I’ve been reading. Obviously CG is a beast but I guess I want to know does the l gem really make him a significantly better champ or just add a nice little perk. I don’t see CGR being a level better because of the gem but I do use him a lot.
For people who voted Angela - is there something she does awakened that makes her the top option for anything specific?

DawsMan

If you use corvus a lot, do corvus. If you use CGR more, awaken CGR, if you have sigs and see yourself using angela, go angela.

JuggerNot

Depends on sig stones, if you have them go for Angela

ReignkingTW

CG depends on where you are in content -- and by looking at your roster I'm guessing he'll help -- but don't sleep on Venompool.