I opened a 5* and a 6* basic crystals back to back within 1 minute of each other. Pulled Venom from both. With nearly 300 champs to choose from, how does that even happen? That’s like a 0.0012% chance.
I pulled a Mojo 6* and then immediately pulled a Mojo 7* when all I needed was a Mojo for my last EoP Carina's challenge after just finishing the Tigta Carina's challenge. But it's still RNG.
The chance is 1 /300 . So only .3%. not an anomaly .
The chance of any champion from the crystal is .3%. so you'll have to start making posts every time you open a crystal
Incorrect. While each crystal has its own individual probability (approx 1 in 300), the probability of pulling the same champ twice in a row becomes 1/300 x 1/300. Or 1/90,000. But since not every playable character is in the basic pools (and I didn’t feel like googling the exact number), I picked 1/290 randomly as a guess. 1/290 x 1/290 = 0.0000119
See, that’s highly improbable. And, from a backend perspective, makes me highly suspicious that when it happens, it’s the result of some kind of temporary server side lag/latency/coding glitch where it produces the same result twice instead of a true double roll.
The chance is 1 /300 . So only .3%. not an anomaly .
The chance of any champion from the crystal is .3%. so you'll have to start making posts every time you open a crystal
Incorrect. While each crystal has its own individual probability (approx 1 in 300), the probability of pulling the same champ twice in a row becomes 1/300 x 1/300. Or 1/90,000. But since not every playable character is in the basic pools (and I didn’t feel like googling the exact number), I picked 1/290 randomly as a guess. 1/290 x 1/290 = 0.0000119
That's not the probability of pulling the same champ twice in a row. The first crystal pull doesn't have any effect on the second pull. What you listed is the chance that a specific character is pulled twice, not any character.
So what you listed is the chance of pulling Venom twice, or the chance of pulling Mojo twice, not the chance of pulling ANY champ twice. 1/300 is for any champ being pulled twice, 1/90,000 is the chance for a specific champ to be pulled twice.
The chance is 1 /300 . So only .3%. not an anomaly .
The chance of any champion from the crystal is .3%. so you'll have to start making posts every time you open a crystal
Incorrect. While each crystal has its own individual probability (approx 1 in 300), the probability of pulling the same champ twice in a row becomes 1/300 x 1/300. Or 1/90,000. But since not every playable character is in the basic pools (and I didn’t feel like googling the exact number), I picked 1/290 randomly as a guess. 1/290 x 1/290 = 0.0000119
Respectfully, you're confusing the chance of pulling Venom back to back with the chance of pulling any champion back to back
The chance is 1 /300 . So only .3%. not an anomaly .
The chance of any champion from the crystal is .3%. so you'll have to start making posts every time you open a crystal
Incorrect. While each crystal has its own individual probability (approx 1 in 300), the probability of pulling the same champ twice in a row becomes 1/300 x 1/300. Or 1/90,000. But since not every playable character is in the basic pools (and I didn’t feel like googling the exact number), I picked 1/290 randomly as a guess. 1/290 x 1/290 = 0.0000119
That's not the probability of pulling the same champ twice in a row. The first crystal pull doesn't have any effect on the second pull. What you listed is the chance that a specific character is pulled twice, not any character.
So what you listed is the chance of pulling Venom twice, or the chance of pulling Mojo twice, not the chance of pulling ANY champ twice. 1/300 is for any champ being pulled twice, 1/90,000 is the chance for a specific champ to be pulled twice.
Yes…you’re making my point. The fact that I didn’t specifically want venom twice does not affect the outcome statistics. You’re saying that if I *had* wanted Venom twice in a row then 1/90,000 would be my odd. But since I didn’t, but I still pulled him twice reduces my odds back to 1/300? That’s nonsensical.
The chance is 1 /300 . So only .3%. not an anomaly .
The chance of any champion from the crystal is .3%. so you'll have to start making posts every time you open a crystal
Incorrect. While each crystal has its own individual probability (approx 1 in 300), the probability of pulling the same champ twice in a row becomes 1/300 x 1/300. Or 1/90,000. But since not every playable character is in the basic pools (and I didn’t feel like googling the exact number), I picked 1/290 randomly as a guess. 1/290 x 1/290 = 0.0000119
No. The probability of two Venoms in a row is 1/300 × 1/300.
The probability of any champion being pulled twice is 1/300.
Yesterday, I pulled Iron man from one crystal and Strom from the next. The probability is 1/300 × 1/300. So is that a statistical anomaly?
The problem is, unless OP wants to learn, it's a statistical anomaly (😉) that they will correct their mistake. Considering that they've already delved into " true roll, lag, backend", it's unlikely.
The problem is, unless OP wants to learn, it's a statistical anomaly (😉) that they will correct their mistake. Considering that they've already delved into " true roll, lag, backend", it's unlikely.
Still wrong. The probability of pulling, say, Rogue and then Venom out of 2 crystals from a pool of 300 champs is only still 1/90,000 - if we're talking about targeting that specific pairing. It is absolutely incorrect to say that pulling any random 5* and then any random 6* is the same probability as pulling a specific pairing: whether it's Venom/Venom or Rogue/Venom. If you're talking a specific pairing, then the probability is 1/90,000 if you're talking any random pairing where you don't care what the outcome is, then probability is actually 1 (100%) because you're always going to get a random 5* and then a random 6*. Pulling any two specific champs in a specific order = 1/90,000.
The chance is 1 /300 . So only .3%. not an anomaly .
The chance of any champion from the crystal is .3%. so you'll have to start making posts every time you open a crystal
Incorrect. While each crystal has its own individual probability (approx 1 in 300), the probability of pulling the same champ twice in a row becomes 1/300 x 1/300. Or 1/90,000. But since not every playable character is in the basic pools (and I didn’t feel like googling the exact number), I picked 1/290 randomly as a guess. 1/290 x 1/290 = 0.0000119
That's not the probability of pulling the same champ twice in a row. The first crystal pull doesn't have any effect on the second pull. What you listed is the chance that a specific character is pulled twice, not any character.
So what you listed is the chance of pulling Venom twice, or the chance of pulling Mojo twice, not the chance of pulling ANY champ twice. 1/300 is for any champ being pulled twice, 1/90,000 is the chance for a specific champ to be pulled twice.
Yes…you’re making my point. The fact that I didn’t specifically want venom twice does not affect the outcome statistics. You’re saying that if I *had* wanted Venom twice in a row then 1/90,000 would be my odd. But since I didn’t, but I still pulled him twice reduces my odds back to 1/300? That’s nonsensical.
1/300 × 1/300 = 1/90,000 if you’re asking for a specific champion twice.
But if you’re asking more generally—what’s the chance that whoever you pull first is the same as the second one, then: • First pull: anything (no restriction). • Second pull: must match the first pull, which has a 1/300 chance.
So the answer in that case is just 1/300.
If you don't care about who you get first, then it's not 1/300, it's 300/300. The odds only become relevant during the second draw when you're trying to match whom you just pulled.
If you were to say BEFORE the pulls “Anyone but Venom, Anyone but Venom …”, specifically saying just Venom, and only Venom, then yes.
But because your point was that they were the SAME (could have been any champ that was the SAME), then it is just 1/300.
Even though you say “well, I didn’t want Venom”. Well, there are probably 280 others that you would say you wouldn’t want either (or at least 250). So getting a duplicate of ANY of the 250 ones you wouldn’t want would agreeably be a little more rare than just 1/300, but not by that much.
I think in general people aren't very good with probabilities in the real world, and also tend to overestimate their ability with statistics in general 🤷♂️ This issue comes up a lot because it's really two different calculations that are easily conflated - 1. pulling a specific champ twice in a row, and 2. pulling the same champ in the next crystal opening.
The chance of you pulling Venom twice in a row is equal to the chance of literally every other outcome occurring, you were just as likely to get Venom twice as you were to get Psycho-Man and then Kushala.
Alright, I get it and stand corrected. Getting any two of the same champion, if I do not care what the champion is = 1/300. Because the 1st crystal is technically 300/300 — it just sets the target for the 2nd crystal; so then the only probability in play is crystal #2, trying to match the 1st crystal: thus 1/300. However if i ONLY wanted Venom, so he was the target of both crystals, then the probability of both crystals comes into play: 1/300 x 1/300 = 1/90,000. So even though the outcome was technically the same — double Venom — the probability jumps to 1/90,000 due to desiring a specific result in BOTH crystals.
They say that you have the same percent chance at pulling any champ in the crystal. If anyone actually believes that, then thats sad an will be disappointed alot. Higher chance at pulling a low tier champ an higher chance at pulling low tiers champs back to back an getting those same champs over an over again. Seen so many people argue about percentages an all of it. Never pull top tier champs over an over.
They say that you have the same percent chance at pulling any champ in the crystal. If anyone actually believes that, then thats sad an will be disappointed alot. Higher chance at pulling a low tier champ an higher chance at pulling low tiers champs back to back an getting those same champs over an over again. Seen so many people argue about percentages an all of it. Never pull top tier champs over an over.
You feel like there’s a lower chance of getting the champions you want because there IS a lower chance of getting the champions you want. If you want to understand what I mean, next time you open a crystal make a list of the champions you want. You’ll probably notice that the list you make will be representative of something like 30 out of the 300 possible champions in the crystal. So yeah, in that case, there’s a 10% chance of you being happy with what you get and a 90% chance of you being unhappy with what you get, but those odds are set by your expectations, not the actual code.
The chance is 1 /300 . So only .3%. not an anomaly .
The chance of any champion from the crystal is .3%. so you'll have to start making posts every time you open a crystal
Incorrect. While each crystal has its own individual probability (approx 1 in 300), the probability of pulling the same champ twice in a row becomes 1/300 x 1/300. Or 1/90,000. But since not every playable character is in the basic pools (and I didn’t feel like googling the exact number), I picked 1/290 randomly as a guess. 1/290 x 1/290 = 0.0000119
the probability of pulling venom twice in a row there is just 1/90000. however, the probability of pulling the same champ twice in a row is 1/300.
Alright, I get it and stand corrected. Getting any two of the same champion, if I do not care what the champion is = 1/300. Because the 1st crystal is technically 300/300 — it just sets the target for the 2nd crystal; so then the only probability in play is crystal #2, trying to match the 1st crystal: thus 1/300. However if i ONLY wanted Venom, so he was the target of both crystals, then the probability of both crystals comes into play: 1/300 x 1/300 = 1/90,000. So even though the outcome was technically the same — double Venom — the probability jumps to 1/90,000 due to desiring a specific result in BOTH crystals.
Thanks for the statistical lesson.
Awesome. Now you can join us the next time someone makes a post
Comments
The chance of any champion from the crystal is .3%. so you'll have to start making posts every time you open a crystal
But since not every playable character is in the basic pools (and I didn’t feel like googling the exact number), I picked 1/290 randomly as a guess. 1/290 x 1/290 = 0.0000119
So what you listed is the chance of pulling Venom twice, or the chance of pulling Mojo twice, not the chance of pulling ANY champ twice. 1/300 is for any champ being pulled twice, 1/90,000 is the chance for a specific champ to be pulled twice.
The probability of any champion being pulled twice is 1/300.
Yesterday, I pulled Iron man from one crystal and Strom from the next. The probability is 1/300 × 1/300. So is that a statistical anomaly?
https://forums.playcontestofchampions.com/en/discussion/319483/what-are-the-odds-of-this/p1
But if you’re asking more generally—what’s the chance that whoever you pull first is the same as the second one, then:
• First pull: anything (no restriction).
• Second pull: must match the first pull, which has a 1/300 chance.
So the answer in that case is just 1/300.
If you don't care about who you get first, then it's not 1/300, it's 300/300. The odds only become relevant during the second draw when you're trying to match whom you just pulled.
Probability of getting CMM - 1/300
Probability of getting Leader - 1/300
So total - 0.0012%.
Kabam needs to investigate this statistical anomaly!!!
But because your point was that they were the SAME (could have been any champ that was the SAME), then it is just 1/300.
Even though you say “well, I didn’t want Venom”. Well, there are probably 280 others that you would say you wouldn’t want either (or at least 250).
So getting a duplicate of ANY of the 250 ones you wouldn’t want would agreeably be a little more rare than just 1/300, but not by that much.
This issue comes up a lot because it's really two different calculations that are easily conflated - 1. pulling a specific champ twice in a row, and 2. pulling the same champ in the next crystal opening.
Getting any two of the same champion, if I do not care what the champion is = 1/300. Because the 1st crystal is technically 300/300 — it just sets the target for the 2nd crystal; so then the only probability in play is crystal #2, trying to match the 1st crystal: thus 1/300.
However if i ONLY wanted Venom, so he was the target of both crystals, then the probability of both crystals comes into play: 1/300 x 1/300 = 1/90,000.
So even though the outcome was technically the same — double Venom — the probability jumps to 1/90,000 due to desiring a specific result in BOTH crystals.
Thanks for the statistical lesson.
First dupe for my 7* rank 3 juggernaut so I'm quite happy with the RNG
It's allll rigggeedd