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100 IIF crystal opening - Does he exist?
The_Savage_Ancient
Really!
How else can you get one! What are the odds literally?
Comments
MEŦAPħҰS
congrats on your 3 star pulls!
for real though, that sucks.
Raganator
The odds are far less than 1%.
NDK13
let me tell you a secret. We ordinary guys will never get him period. I might have opened easy 500 of those shards. I even got him once but then the game crashed and when I login again he's not there and I get a tech sig stone. I sent a ticket and the reply came that my net connection isn't stable that's why I experienced lag. What a load of BS. I stopped caring anyway.
Eb0ny-O-M4w
I opened 200 of them until I get the 3-star. Opened more 200 and didn't got him again.
All about luck
RexDeus
Open 100 2* max sig crystals get nothing open 1 3* max sig got a 4* IIF. Never know what you're going to get.
Dusky_Dawn
He does exist, I've seen it happen, and I also believe someone has the 5 star version of him
Slig
I've opened over 1000 of the crystals and still haven't gotten him.
Rotmgmoddy
I save myself the potential disappointment by automatically assuming I'm just getting the most common reward: shards.
But yea, he does exist, just really really rare. You need to be pretty lucky to get him. Don't be too upset if you don't, I believe he is just a champion for bragging rights. For utility, I think even the regular IF is better than him.
DarkestDestroyer
I got a 3* one a couple weeks ago.
He is in there
Kronos987654321
I imagine he's like 4* punisher in arena crystals
unknown
This content has been removed.
Joseph703
Got him on my first crystal:/ Super lucky
Jaffacaked
I got him in under 50
GroundedWisdom
He's in there. One of the rarest pulls in the game. It's all up to the RNG.
Kabam Zibiit
The_Savage_Ancient
wrote:
»
Really!
How else can you get one! What are the odds literally?
Hey it looks like some other players have gone ahead gone ahead and answered your question here. The Max Signature Ability Crystals do have a rare chance to reward an Immortal Iron Fist. Since the answer to this question has been provided, I'm going to go ahead and close this discussion.
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