1/162. I think if you’re specifically talking about the hulk pull.
What are the odds of this even happening.
1/162. I think if you’re specifically talking about the hulk pull. I don't think it's 1/162. Shouldn't it be 0.019897
1/162. I think if you’re specifically talking about the hulk pull. I don't think it's 1/162. Shouldn't it be 0.019897 169 champs available as 6*s. 7 are not in the basic yet.
The odds are one thing. The amount this occurs is another. It's very common for Rosters to lean to one side, or not lean to another. Eventually, they fill in.
4/7I win
Assuming independence of event:P(4 of 7 science) = = P(sci)^4 * P(!sci)^3 = P(#of science in crystal / # in crystal)^4 * P(1 - (#Sci / #crystal))^3
Assuming independence of event:P(4 of 7 science) = = P(sci)^4 * P(!sci)^3 = P(#of science in crystal / # in crystal)^4 * P(1 - (#Sci / #crystal))^3 Why would you use this equation instead of a binomial distribution equation? I'm kinda confused
Assuming independence of event:P(4 of 7 science) = = P(sci)^4 * P(!sci)^3 = P(#of science in crystal / # in crystal)^4 * P(1 - (#Sci / #crystal))^3 Why would you use this equation instead of a binomial distribution equation? I'm kinda confused Poisson distribution > binomial distribution
Assuming independence of event:P(4 of 7 science) = = P(sci)^4 * P(!sci)^3 = P(#of science in crystal / # in crystal)^4 * P(1 - (#Sci / #crystal))^3 Why would you use this equation instead of a binomial distribution equation? I'm kinda confused Poisson distribution > binomial distribution This isn’t a poisson distribution tho