The math doesn’t seem to work quite right...
Mfalls
Member Posts: 94 ★
So we just lost this war matchup, but based on the numbers the math is possible but highly improbable. What are the odds that the other team would die 8 more times and only have 1 fewer attack bonus?
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The opposition could get 5 kills overall but if they’re all on different nodes then that’s 5 attack bonuses
Others have already commented on how this could happen mathematically, but I'll address the question of how likely it is. It is actually not all that unlikely.
The max attack bonus possible is 495 (which includes traversing empty nodes). You had 441. So you lost 54. Three of those come from the defender you left behind. So you lost 51 attack bonuses to deaths and they got 56 kills. That suggests five of your deaths were on nodes that already had three kills. They had 440 attack bonuses and thus lost 55. They didn't leave any defenders behind and your side got 64 defender kills. So 9 of their deaths were on nodes with more than three kills.
So your side had five deaths on depleted defender nodes and their side had nine deaths on those depleted nodes. That's not a terribly weird end result.
When you break it down like that it makes a lot more sense than it did to me sense I hadn’t ever heard it broken down like that thanks!
Actually... very high.
After 3 kills, it doesn't matter. How many times have you seen a defender with more than 3 kills?
Every kill after that is lagniappe and doesn't mean anything.
Congratulations: this is the first time I've looked up something weird someone typed into the forums and discovered it was a legitimate English word spelled correctly I was unaware of.
Challenge accepted I’m tossing in random obscure words in every post going forward
Chuck in words that you've made up but he'll still have to look up anyway.
That would just be bargantuous
huh...
Edit: dammit I fell for it
It's kind of a southern Louisiana special. We use it a lot.