That means to get 1 is a 3/100 chance. To get 2 is 3/100 x 3/100. To get 3 is 3/100 x 3/100 x 3/100 which is 27/1000000 chance or 0.000027

Sorry but you're wrong ... I get what you did there but getting consecutive 4*s has low probability on it's own .... And getting 3 consecutive 4*s ... Well π€·π»ββοΈ .... I am sure it's lower than what you stated. Or am i wrong? ππ I am dumb ... I don't know π€¦π»ββοΈ

That means to get 1 is a 3/100 chance. To get 2 is 3/100 x 3/100. To get 3 is 3/100 x 3/100 x 3/100 which is 27/1000000 chance or 0.000027

Sorry but you're wrong ... I get what you did there but getting consecutive 4*s has low probability on it's own .... And getting 3 consecutive 4*s ... Well π€·π»ββοΈ .... I am sure it's lower than what you stated. Or am i wrong? ππ I am dumb ... I don't know π€¦π»ββοΈ

It's independent event probability, so yes, TP33 is right.

@Thicco_Mode every crystal it stays 3%. I might have said it wrong.

If you open a crystal and get a 4 star. you have a 3% chance to get a 4 star the crystal after. If you pulled 2, and want to pull another, you have a 3% change to get a 4 star.

It does not matter how many 4 stars you have pulled, the chances of pulling the next 4 star is still 3%.

But I must admid, from a pure probability standpoint, (3%)^3 is correct. Even if it is completely irrelivant.

@Thicco_Mode every crystal it stays 3%. I might have said it wrong.

If you open a crystal and get a 4 star. you have a 3% chance to get a 4 star the crystal after. If you pulled 2, and want to pull another, you have a 3% change to get a 4 star.

It does not matter how many 4 stars you have pulled, the chances of pulling the next 4 star is still 3%.

But I must admid, from a pure probability standpoint, (3%)^3 is correct. Even if it is completely irrelivant.

Yeah I think you just worded it wrong. This is correct

@Thicco_Mode every crystal it stays 3%. I might have said it wrong.

If you open a crystal and get a 4 star. you have a 3% chance to get a 4 star the crystal after. If you pulled 2, and want to pull another, you have a 3% change to get a 4 star.

It does not matter how many 4 stars you have pulled, the chances of pulling the next 4 star is still 3%.

But I must admid, from a pure probability standpoint, (3%)^3 is correct. Even if it is completely irrelivant.

Yeah I think you just worded it wrong. This is correct

Incorrect. The OP wasnβt asking the probability of a single opening. He was asking the probability of pulling 3 consecutively, which is not the same.

@Thicco_Mode every crystal it stays 3%. I might have said it wrong.

If you open a crystal and get a 4 star. you have a 3% chance to get a 4 star the crystal after. If you pulled 2, and want to pull another, you have a 3% change to get a 4 star.

It does not matter how many 4 stars you have pulled, the chances of pulling the next 4 star is still 3%.

But I must admid, from a pure probability standpoint, (3%)^3 is correct. Even if it is completely irrelivant.

Yeah I think you just worded it wrong. This is correct

Incorrect. The OP wasnβt asking the probability of a single opening. He was asking the probability of pulling 3 consecutively, which is not the same.

This reply answers a question that was not asked.

I was referring to his last statement This is what the op was asking

That means to get 1 is a 3/100 chance. To get 2 is 3/100 x 3/100. To get 3 is 3/100 x 3/100 x 3/100 which is 27/1000000 chance or 0.000027

Sorry but you're wrong ... I get what you did there but getting consecutive 4*s has low probability on it's own .... And getting 3 consecutive 4*s ... Well π€·π»ββοΈ .... I am sure it's lower than what you stated. Or am i wrong? ππ I am dumb ... I don't know π€¦π»ββοΈ

So.. if you know that he's wrong.. you must know how to make the calculation yourself.. so why don't you do that?

@Thicco_Mode every crystal it stays 3%. I might have said it wrong.

If you open a crystal and get a 4 star. you have a 3% chance to get a 4 star the crystal after. If you pulled 2, and want to pull another, you have a 3% change to get a 4 star.

It does not matter how many 4 stars you have pulled, the chances of pulling the next 4 star is still 3%.

But I must admid, from a pure probability standpoint, (3%)^3 is correct. Even if it is completely irrelivant.

I wish people would stop regurgitating this from whichever Google search or common core math class from which you learned this and thought it was clever. It is not irrelevant because the OP asked the question. He was pleasantly surprised and was just curious what the probability is of pulling 3 consecutive 4* champs. The question is fine and the answers given are correct. Your response doesn't mathematically disprove the calculations used to obtain the probability. It is in fact part of the underlying assumptions of the equation. If outcomes were instead contingent on previous pulls, then the answers given above would be incorrect.

It's a stupid question because outcomes for specific pulls are independent? Not to the OP.

One time they were selling these crystals that would give you a cavalier grandmaster or some other kind. Cavalier was the most rare and i got it and then pulled a six from that one.

## Comments

1,176β β β βThat means to get 1 is a 3/100 chance.

To get 2 is 3/100 x 3/100.

To get 3 is 3/100 x 3/100 x 3/100 which is 27/1000000 chance or 0.000027

67βOr am i wrong? ππ I am dumb ... I don't know π€¦π»ββοΈ

137β β1,168β β β β4,192β β β β206β513β β β2,820β β β β β206βIf you open a crystal and get a 4 star. you have a 3% chance to get a 4 star the crystal after. If you pulled 2, and want to pull another, you have a 3% change to get a 4 star.

It does not matter how many 4 stars you have pulled, the chances of pulling the next 4 star is still 3%.

But I must admid, from a pure probability standpoint, (3%)^3 is correct. Even if it is completely irrelivant.

719β β β1,168β β β β225β βI think*

*edit to add qualifier.

2,820β β β β β996β β β βThis reply answers a question that was not asked.

2,820β β β β βThis is what the op was asking

719β β βOr 0.0027%

It's very rare.

32βPhew!

686β β β1,233β β β β397β β βI wish people would stop regurgitating this from whichever Google search or common core math class from which you learned this and thought it was clever. It is not irrelevant because the OP asked the question. He was pleasantly surprised and was just curious what the probability is of pulling 3 consecutive 4* champs. The question is fine and the answers given are correct. Your response doesn't mathematically disprove the calculations used to obtain the probability. It is in fact part of the underlying assumptions of the equation. If outcomes were instead contingent on previous pulls, then the answers given above would be incorrect.

It's a stupid question because outcomes for specific pulls are independent? Not to the OP.

996β β β βYouβre all invited to my home casino.

1,493β β β βI'm not sure though.

56β1,209β β β737β β β63β80β571β β β513β β β651β β β