First time ever..

I rolled the dice on the new potential 5* Archangel and wasted $40. Got all 3*. Dont do it, waisting money on Crystal pulls is dumb.. im dumb lol.,

Comments

Kabam Zibiit

Ok so this is non-constructive and has turned more than a little argumentative and personal so I'm going to be closing this down.

Mhykke

Hubris_hater wrote: »

Cihag wrote: »

Hubris_hater wrote: »

Quatre_1988 wrote: »

So...I opened 130 of those crystals today. I ended up pulling 2 5 star groots, and a 5 star padlock. The odds of me pulling 2 of the same champ are significantly lower than pulling the featured champ.ive opened every featured grand master crystal since blade some more crystals then this time. And haven't gotten a single featured champ yet.

1 - who is padlock
2 - The odds of getting the same champ twice is the same as getting any champ. When will people actually read that no crystal pull affects any other. Its the same odds on every pull as to who you get. Seriously, I don't understand why people need to be told this, why would one affect the next one? Toss a coin. Toss it again. Did the first time have any effect on the 2nd one, no, of course it didn't

Well, math tells you otherwise...

In your coin example: Yes, the odds for getting heads on the first try are 0.5 and yes, the odds for getting heads the second time are also 0.5.

BUT: The odds for getting heads BOTH times are actually 0.5 * 0.5 = 0.25. So the odds are lower for getting the same result twice.

Same goes for the champs in the crystal.

Just my 2 cents...

Mate, that is COMPLETELY WRONG lol. One does not affect the other. Its because people multiply or add the odds like this that they get upset when the results dont match the ones they made up by doing this incorrectly!

If you use your wrong way, and spin a coin 10 times, then according to you the chances of getting a heads would be 0.0009%! Spin it 15 times and your odds of getting a heads on a 2 sided coin would drop to 0.000002%!!

Surely you can see that is so wrong its unreal. The chance of getting a heads again is 50% still

Actually, he is correct. This is a common misunderstanding. You are confusing the fact that each flip is an independent event (50% each time) vs calculating the odds of a certain result over a certain number of occurrences (coin flips in this example).

Each coin flip is 50% heads or tails. So if you were to ask "I'm flipping a coin, what are my odds of getting a tails?" The answer would be 50% (ignoring slight differences for weight distribution between the 2 sides). If you were to do it again and ask the same thing, the answer would again be 50%. And a third time, and a fourth time, etc. etc. But before you flip any coins, if you were to ask "What are my odds of getting 2 heads total on my next 2 coin flips?" Then the answer is indeed 25% (.50 * .50)

And to use your example, yes, before you started flipping a coin, if you were to ask "what are the odds of getting 10 heads on my next 10 coin flips?" The answer would be .000976563. Even though each action is independent of the one before it, before you start flipping, the odds of getting heads every time over 10 flips are not 50%. If you were to ask "what are the odds of getting 15 heads on my next 15 coin flips?" The answer would be .0000305.

But don't take my word for it. There are plenty of calculators that will calculate the odds (note, they don't all just spit out "50%" every time):

http://calculator.tutorvista.com/coin-toss-probability-calculator.html