Explain me the Algo Kabam

When I woke up in the morning the final chapter for Gwenpool arena was out and people were opening crystals like crazy. 70% of my alliance members got IP as 2*s 3*s 4*s and 5s*. Explain me the algorithm kabam uses for those dissapointment crystals. You say cinematic crystal has 4% chance for 4* hero but trust me that is like 60% chance to get an IP. Same is the issue with legendr, 5* and 4* hero crystals. We don't really deserve to be treated like this for our efforts. Please do something about that and stop pissing your users off.

Comments

Midknight007

Notice the time stamps being hours and minutes apart? Seems like it is blind unluck in this case. I have seen feeds with multiple pulls with the same champ. Realize the crystal has 20 champs... 5% per champ (not including if there is a range of 3-5* or 2-4*). The chances are higher than usual that people will pull the same champ (especially over hours of game play). If there were seconds between the pulls, it would be a little more suspect of an issue.

Saket_123

Out of 30 Members, almost everyone got either a 4* or 5* IP which is suspicious enough for me. Even I opened 2 cinematic crystals Just now and got a 2* IP and 3* Thor. Look at those mass openings of 2* crystals from the arena on youtube. Maximum champ found was IP.

Midknight007 wrote: »

Notice the time stamps being hours and minutes apart? Seems like it is blind unluck in this case. I have seen feeds with multiple pulls with the same champ. Realize the crystal has 20 champs... 5% per champ (not including if there is a range of 3-5* or 2-4*). The chances are higher than usual that people will pull the same champ (especially over hours of game play). If there were seconds between the pulls, it would be a little more suspect of an issue.

NoOnexRO

If you really think that the code has pure random selection and each champion has equal chances to be obtained from a crystal... clearly you still believe in Santa also.

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Sceptilemaniac

I don't know about that, but I duped my 5* star lord as my 6th 5 star.
Yeah, 2 outta six were star lords..
And I'm still waiting for a 3,4, or 5* IP

DOKTOROKTOPUS

i got 5* iron patriot and 2 times 4* starlord

GroundedWisdom

Haven't seen one in our feed. If that was the case, everyone would get IP. What you have is coincidental.

hephaestus

My past five 5* pulls in order:

Iron Man
Iron Man
Iron Patriot
Iron Patriot
Iron Man

No way the RNG is equal chances for everything. The chances of this are infinitesimal if what they say is true. Until they release the exact formula / code, I won't believe them. I'd feel this way even if the pulls were good. The odds of this happening are far from random no matter who you place in the slots.

djr17

Any string of 5 champs have the exact same infinitesimally small chance of happening, be they IM,IM,IM,IM,IM or Blade, Sparky, GR, Iceman, AA

ghostgigi2

the algorithm is not equal for everyone, if you spend money in the game you will have more luck (there is plenty of evidence) otherwise it is not possible.
I opened 3 crystals 5 * = 3 gambit in a row

TwmR

ghostgigi2 wrote: »

the algorithm is not equal for everyone, if you spend money in the game you will have more luck (there is plenty of evidence) otherwise it is not possible.
I opened 3 crystals 5 * = 3 gambit in a row

There's is zero evidence of this unless you would like to enlighten me and show it

Demonzfyre

ghostgigi2 wrote: »

the algorithm is not equal for everyone, if you spend money in the game you will have more luck (there is plenty of evidence) otherwise it is not possible.
I opened 3 crystals 5 * = 3 gambit in a row

#fakenews #tinfoilhatsociety please stop spreading rummors like this.

ghostgigi2

if you are engineers you can understand, otherwise I advise you to go to do programming classes and take a look at the source code. @Demonzfyre @TwmR

ps: I do not care about the champion, i'm an End Game Player

Demonzfyre

ghostgigi2 wrote: »

if you are engineers you can understand, otherwise I advise you to go to do programming classes and take a look at the source code. @Demonzfyre @TwmR

ps: I do not care about the champion, i'm an End Game Player

You are 100% wrong

Manumission18

Ha ha I got 5* Yondu 4* IMIW and 5* hela and finally a duped 4* Original thor

TwmR

ghostgigi2 wrote: »

if you are engineers you can understand, otherwise I advise you to go to do programming classes and take a look at the source code. @Demonzfyre @TwmR

ps: I do not care about the champion, i'm an End Game Player

I don't need to be an engineer or go to programming classes to know there is not evidence to back up your claims.

I've never spent a penny on this game yet as 5* I have
Duped voodoo
Void (awakened with gem)
Hyperion
Quake
Iceman
MS
Hulk rag
Duped hela
Duped AA
Luke cage

The1_NuclearOnion

Got 3 Yondus 4*, 4*, 5*

The1_NuclearOnion

Demonzfyre wrote: »

ghostgigi2 wrote: »

if you are engineers you can understand, otherwise I advise you to go to do programming classes and take a look at the source code. @Demonzfyre @TwmR

ps: I do not care about the champion, i'm an End Game Player

You are 100% wrong

I really don;t know if he's wrong or not. You either for that matter. We KNOW, for a FACT it is possible. Is it true?
You and the rest of us will never know!

Paralyzer

I got 5 star wasp and 4 star starlord

ghostgigi2

@TwmR

i'm no saying yo have to spend, but there is another chance (plenty of videos in russian) may be they a hacker

anyway, Good Luck for all

hephaestus

djr17 wrote: »

Any string of 5 champs have the exact same infinitesimally small chance of happening, be they IM,IM,IM,IM,IM or Blade, Sparky, GR, Iceman, AA

How do you figure?

"EVENTS IN SUCCESSION

The probability that independent events will happen in succession, is the PRODUCT of those events.

For example, while the probability that one toss of a coin will turn up heads, is 1/2 (or one chance out of two) --the probability that two tosses of a coin will produce two heads in a row, is 1/2 X 1/2 = 1/4 ...or one chance out of 4.

Taking the example further, the probability that three tosses of the coin will produce three heads in a row, is the product of those three independent events, or 1/2 X 1/2 X 1/2 = 1/8 ...or one chance out of eight.

Applying this principle to the shuffled deck of 52 cards, the probability of drawing the Ace of Spades two times in a row,
is 1/52 X 1/52 = 1/2704 ...or one chance out of 2704"

So say there are 100 champs in the basic pool. (I don't know how many there are, I think it's more?) The chances of me drawing IM or IP on any given pull would be 2/100, which reduced to 1/50. To do that 5 times in a row = 1/50 * 1/50 * 1/50 * 1/50 *1/50 = 0.00000032%. Either I'm exceptionally lucky / unlucky (I don't care what you want to call it) or the odds are not truly what have been stated.

If you think my math is wrong, please provide an example of how.

John757

The chances of winning the lottery are small, yet someone seems to win it 🤔

John757

You have a 50% chance of surviving a 40 foot fall, yet a man has fallen 18,000 feet and only sustained a sprained leg. Anything is possible

Kabam Lyra

Hello all,

To clarify, unless otherwise stated, you are not more or less likely to get any certain Champion in a Crystal. For example, if you open a 4-Star Hero Crystal, every Champion has the exact same odds of dropping, and if you open a PHC, you have the exact same chance to get any of the Champions contained within.

There are not different Drop Rates for different Champions in Crystals, unless we specifically state it. Hope that helps clear up the confusion!