Zone 2 safe unsolvable
AustinU823
Member Posts: 84 ★★
I had time on my hands while watching a show and tried every possible combination for the hints we have so far, knowing the code is 2 __ 8 and none of them unlocked the safe. I’m assuming the safes will only be crackable one week at a time, just in case you try to waste your time solving it now
9
Comments
Or just wait a few days.
I hadn't considered this.
With enough organization and planning... an alliance could brute force the combination for the second safe without finishing any of the objectives...
Challenge extended.
It appears that the note things we get do display the numbers of the combination. Therefore if 2 and 8 are in the combination, here is the list according to chatGPT: (apologies for the long list
Certainly, here is the list of all possible 4-number combinations with repetition allowed and the order matters that include the numbers 2 and 8 grouped into columns and rows:
2 8 1 1 | 2 8 1 2 | 2 8 1 3 | 2 8 1 4 | 2 8 1 5 | 2 8 1 6 | 2 8 1 7 | 2 8 1 8
2 8 2 1 | 2 8 2 2 | 2 8 2 3 | 2 8 2 4 | 2 8 2 5 | 2 8 2 6 | 2 8 2 7 | 2 8 2 8
2 8 3 1 | 2 8 3 2 | 2 8 3 3 | 2 8 3 4 | 2 8 3 5 | 2 8 3 6 | 2 8 3 7 | 2 8 3 8
2 8 4 1 | 2 8 4 2 | 2 8 4 3 | 2 8 4 4 | 2 8 4 5 | 2 8 4 6 | 2 8 4 7 | 2 8 4 8
2 8 5 1 | 2 8 5 2 | 2 8 5 3 | 2 8 5 4 | 2 8 5 5 | 2 8 5 6 | 2 8 5 7 | 2 8 5 8
2 8 6 1 | 2 8 6 2 | 2 8 6 3 | 2 8 6 4 | 2 8 6 5 | 2 8 6 6 | 2 8 6 7 | 2 8 6 8
2 8 7 1 | 2 8 7 2 | 2 8 7 3 | 2 8 7 4 | 2 8 7 5 | 2 8 7 6 | 2 8 7 7 | 2 8 7 8
2 8 8 1 | 2 8 8 2 | 2 8 8 3 | 2 8 8 4 | 2 8 8 5 | 2 8 8 6 | 2 8 8 7 | 2 8 8 8
I hope this format is helpful for you!
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Well, to start, finding out all possible combinations. Which is not 10k. Then you would need to try and think like Kabam and brainstorm some good use cases for chatGPT to use to help you. It might not help, but it could. I guess thinking more on it, you're probably right. It would require more information than currently available.
chatGPT:
To find the number of possible 4-number combinations that include the numbers 1 through 8, we can use the formula for combinations.
The number of combinations of n items taken k at a time is given by the formula:
nCk = n! / (k! * (n - k)!)
where n! (n factorial) is the product of all positive integers up to n, and k! is the product of all positive integers up to k.
In this case, we want to find the number of combinations of 4 numbers taken from a set of 8 numbers (1 through 8). Using the formula above, we get:
8C4 = 8! / (4! * (8 - 4)!)
= 8! / (4! * 4!)
= (8 * 7 * 6 * 5) / (4 * 3 * 2 * 1)
= 70
Therefore, there are 70 possible 4-number combinations that include the numbers 1 through 8.
My follow up: what if they can be in any order and numbers can be reused?
If the 4-number combinations can be in any order and the numbers can be reused, we can use the concept of permutations with repetition.
To find the number of permutations with repetition of n items taken k at a time, the formula is:
n^k
where n is the number of items and k is the number of slots to fill.
In this case, we have 8 numbers to choose from and we want to fill 4 slots with repetition allowed. So, using the formula above, we get:
8^4 = 8 x 8 x 8 x 8 = 4,096
Therefore, there are 4,096 possible 4-number combinations with repetition allowed and the order matters that include the numbers 1 through 8.
1111
1112
1113
.....
8886
8887
8888
MEAN DTHE BOYS
is it only math?
Dividing by various Primes to get different single digit results each between 2 and 9 for each digit's place, then translating that to alphabet based on numeric keypad on phone (2 is either abc, 3 is def, etc), then doing a puzzle to figure out what words can be made from each of the place's 3 character options.
—OR—
How about taking the codes (1st being 3174) and splitting them apart.
Using each 2 digit number (31 and 74) as a lookup into ASCII code table to see what character they translate into.
And in the end you’ll have a 6 character word.
Could maybe spell out SPIDEY (as an example).
So just work backwards, what is ASCII code for I and D, and then week after for E and Y.
You’d have to account for them using some initial offset into the table though.
And even if you select the Offset used so that 31 corresponds to Capital “S”, then lower case “p” is only 29 places away, not 43 (74 minus 31).
About as confusing as that Prime Number MEAN DTHE BOYS