**KNOWN ISSUE WITH SIDE QUEST KEYS**

We are aware of an issue impacting some Summoners, resulting in the loss of their stash of SQ entry keys.

The team will be redistributing lost keys.

Timeline is uncertain.

(Slightly) More information here.

We are aware of an issue impacting some Summoners, resulting in the loss of their stash of SQ entry keys.

The team will be redistributing lost keys.

Timeline is uncertain.

(Slightly) More information here.

# Who ya Foolin with No foolin Pool’s Gold? Drop rate is WACK!!

Dawill76
Posts:

**22**★
How many of you guys have ever gotten a 6* Goldpool from this crystal? I don't know how Kabam calculates their percentage but I’ve been spun these crystals every time they have this event and have never opened anything other than gold (and mostly the smallest gold too). Is the percentage based on each event or the life of your account every time the event comes around? Cause I’m I would have at least gotten the .20% 5* Goldpool by now.

1

## Comments

2,225★★★★★1,705★★★281★★★4,027★★★★★514★★★20,712★★★★★1,693★★★★★36,072★★★★★(I still have a personal vendetta. You will be mine! Muahahaha!)

*At least they gave us a 4-Star.

57★Now if only I can have this kind of luck with 6* Punisher, I’d be ecstatic, heh!

30★52★18,285GuardianHave you opened one thousand fourhundred ninety six Goldpool crystals?

I know what you are probably thinking. A 0.2% chance is one in 500, so it must be certain that you'd get him after 500 crystals. That's not true, for the simple reason that if everyone got him after 500 crystals, the drop odds would only be one in 500 if

no one, evergot him twice. Since the odds of getting him more than once is not zero, the odds of getting him at least once in 500 crystals must be less than 100%.It is theoretically possible to miss every single time, it is just increasingly improbable. But not impossible.

For the mathematically inclined, as the numbers get large the odds of NOT getting something in X drops when the odds of getting it are one in X is about 0.368. That's because the way we calculate the odds of not getting drop D when the odds of getting that drop are one in X is (1 - 1/x) ^ R, where R is the number of rolls. So if the odds are one in 500, the odds of not pulling in twenty rolls is (1 - 1/500) ^ 20 = 0.998 ^ 20 ~= 0.96. The odds of not pulling in 500 openings are (1-1/500)^500 ~= 0.3675. The sequence (1 - 1/x)^X is a rapidly converging series. The limit as x->∞ of (1-1/x) ^ x is 1/e, which is 0.367879...

21,776★★★★★3,574★★★★★10,236Guardian**anyone else feel as if the Feedback options should have another Reaction added (besides “Insightful” or “Awesome”) for all of @DNA3000 's replies like these.

Should be a new Reaction we could give called “MATH”.

635★★★★222★★★276★761★★★18,285Guardian1,050★★★1,480★★★★