Any mathematicians in the house?
Skydad23
Member Posts: 556 ★★★
I would really like to know the odds this.
There are 38 science champs you can get in the science abyss nexus Crystal I have 37 of those champs I am trying to get Hulk the one Champion I do not have.
I opened eight science nexus abyss crystals
So that’s 10 different champions in each Crystal so basically 80 shots at getting him. Of course I did not get him. What are the odds of having 80 shots at some thing? And not actually getting the one single one you do not have????? I would love to know the odds of that
There are 38 science champs you can get in the science abyss nexus Crystal I have 37 of those champs I am trying to get Hulk the one Champion I do not have.
I opened eight science nexus abyss crystals
So that’s 10 different champions in each Crystal so basically 80 shots at getting him. Of course I did not get him. What are the odds of having 80 shots at some thing? And not actually getting the one single one you do not have????? I would love to know the odds of that
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Comments
P(Not getting Hulk in 8Abyss Nexus crystals)= P(Not getting Hulk in one abyss Nexus Crystal)^8= 0.726 ^8= 0.086
≈ 8.6%. . Not too shabby tbh
There are 38 science champions in the crystal you get 10 shots in each crystal that’s more than a 25% chance in each crystal and when you stack on the odds that the one I would not get is the one of the 38 I did not have having all 37 others percentage seems astronomical to not get that one?
1/38 chance each attempt, 80 attempts.
1/38 ≈ 2.6%. (Each attempt)
2.6%(.0026) x 80 ≈ 2.1(210%)
So you had a 210% chance of getting your one champ, but you didn't. Thats if every champ had an equal chance of dropping and it's an average. So this is an outlier right? Sorry I'm trying my best with this math.
What you did wrong was had 1/38 over 80 attempts, when it is 1/38 over a decreasing pool size, over 8 tries.
For 1 crystal the chance that you do not get him is: 37/38 * 36/38 * ... * 28/38 which is roughly 0.2013 (20.13% chance).
For 8 crystals it is: 0.2013^8 = 0.000002696 (which is 0.00027%) that is extremely low chance.
See when you say 1/38 + 1/37 + ... you ignore the fact that it is impossible to pull him more times in 1 crystal (also production must be used instead of addition)
EVER.
So to correct myself, this is how to calc it, exactly as you have said before:
I will use the notation (n k) for n choose k (which is n! / (k! * (n-k)!) )
- For 1 crystal the chance you don't get him is: (37 10) / (38 10) = 0.7368 (73.68%)
- For 8 crystals it is: 0.7368^8 = 0.0869 (8.69%)
P.S. I'll think about myself now...
Otherwise people wouldn't have had to open 30-40 crystals and then still come to forums to complain about not getting
the champion they desire
It's 1/38 for each crystal
So he just had 2.6 % chance of getting hulk in each crystal
And he will have 2.6% chance of getting hulk in each crystal even if he opens 100 abyss nexus
But still it's quite sad that you couldn't get him
I really love playing my r2 hulk in BGs
But give me that 6* Juggs Kabam
You’re forgetting the very important part that the one and 38 you’re choosing one of 10 getting a choice of 10 changes, if there is 40 of some thing and you open a box and there are 10 of that 40 in there with no duplicates and you get to pick one of the 10 that is 25% figuring this is one and 38 choosing one out of 10 the odds of each crystal is higher than 25%
It is a 10-CHOICE NEXUS.
The potentials of all of the 10 choices of the Nexus (like the 3-choice Nexus's) are dependent on each other in that you will not be given the same champ for multiple of the 10 choices.
So calculate that first (which is what the 38 and 10x calculations are first doing), and THEN proceed to do the (as you say) independent relation for the 8 of those such Nexus's.
(and just to further explain it in more understandable terms)..
Odds of NOT getting in SLOT #1 of 10 choices of Nexus is 37/38
And then of NOT getting in SLOT #2 is 36/37
Etc, down to final SLOT being 28/29.
Numerators going from 37, 36, 35 .. 28
Denominators going from 38, 37, 36 .. 29
Odds for Not getting for that particular Nexus boils down to (9 of the 10 numbers are same in Numer. and Denom.) 28/38.
Which is 0.7368.. (73.68 chance of NOT getting in a single 10-choice Nexus)
Then take that, as correctly said before, as an “8 factorial” (8 Nexus crystals).
To become 0.0869 (8.7% chance you will NOT get him).
Is that right ?
( @AverageDesi , where was your original 0.726 coming from, instead of 0.7368 above. Or just typo between switching apps doing calculations ??)
Woo oo ooo, baby
It seems like 0%, but it isn't.
I've been saving for the 2022 selector july 4th deal and bingo, crazy 100%!!!
This one is pretty simple. You get ten draws out of a pool of thirty eight. Each draw is unique (not duplicate) which means the crystal contains ten out of thirty eight of the possibilities. Therefore, the odds of the target being in the crystal is 10/38 ~= 26%, the odds of the target not being in the pool is 28/38 ~= 74%.
The odds of missing the target after eight Nexus crystals is thus (28/38)^8 ~= 8.7%. The odds of landing the target after eight Nexus crystals is 91.3%. Alternatively, the odds of missing the target after eight Nexus crystals is about one in 11.5. If twenty three players do this, you'd expect on average two of them to miss with all eight Nexus crystals.
This reproduces @AverageDesi 's calculations, except for the small typo (0.736, not 0.726), and @SummonerNR 's calculations except the per Nexus calculation is more straight forward.
This is uncommon, but not extremely rare. In an alliance of thirty people, you'd expect to see two or three players suffer this fate.