Math experts help me here(dual class crystal probability)
Roman4544
Member Posts: 85 ★
I really want to duplicate my Ant Man, let's say(I don't know the exactly numbers of champions of science and mystic in total, but it doesn't matter) there are 45 champions in total of these classes. What is the probability that in 5(50k shards) tries I'm able to get my Ant boy in one of them?
Ps: sorry if there is some grammar error, latino here.
Ps: sorry if there is some grammar error, latino here.
9
This discussion has been closed.
Comments
Each crystal has individual probabilities.
Lets say you have 2 % chance for 1 crystal.
The next crystal also has only 2 % chance.
The probability doesn't add up like that.
Thats why it's called probability.
Correct me if i am wrong but i this is what i know.
Just pop open those and don't hope anything.
If u get him, you will feel happy and if you don't get him, just try another time.
With 6 dice there would actually be 46,656 available outcomes of which 31031 have a positive outcome of you only need one 6, so the odds would be 66.51%
So your first instinct is right. Even though the events are independent of each other, having more opportunities to get the outcome you want increases your odds.
(5/45) ×100~ 11%
P = 1/N
P = 1/45 = 2.22%
The probability will be the same for every crystal opening but the probability of success that you will pull him after a number of tries can be computed with:
1-(1-P)^n
where n is the number of tries:
1-(1-0.0222~)^5
10.63%
1-(1-0.0222...)^50 = 67.49%
Not even close to 100%
ps: the detail you mentioned(about one time only and at least) reminded of my math teacher who always make sure that we pay very close attention to the whole title of the question and their tricky meaning