**Mastery Loadouts**
Due to issues related to the release of Mastery Loadouts, the "free swap" period will be extended.
The new end date will be May 1st.
Due to issues related to the release of Mastery Loadouts, the "free swap" period will be extended.
The new end date will be May 1st.
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Can someone calculate the probability of this??
X_E_Cutioner
Posts: 155 β
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That means to get 1 is a 3/100 chance.
To get 2 is 3/100 x 3/100.
To get 3 is 3/100 x 3/100 x 3/100 which is 27/1000000 chance or 0.000027
Or am i wrong? ππ I am dumb ... I don't know π€¦π»ββοΈ
If you open a crystal and get a 4 star. you have a 3% chance to get a 4 star the crystal after. If you pulled 2, and want to pull another, you have a 3% change to get a 4 star.
It does not matter how many 4 stars you have pulled, the chances of pulling the next 4 star is still 3%.
But I must admid, from a pure probability standpoint, (3%)^3 is correct. Even if it is completely irrelivant.
This reply answers a question that was not asked.
This is what the op was asking
Or 0.0027%
It's very rare.
Phew!
Youβre all invited to my home casino.
I'm not sure though.